The array will be divided into two parts: sorted and unsorted. In our example, the sorted part comes before the unsorted part; however, it may be the opposite with some slight changes.
View all Courses. All rights reserved. Courses Pricing. How to implement Selection sort in Java. The algorithm works as follows: Initially, the whole array is unsorted. Find the minimum of the unsorted part and swap it with the first element.
Now, consider the minimum number chosen in the previous step as part of the sorted array. The size of the sorted part grows this way. Continue steps one through three until there are no elements left in the un-sorted part. In every iteration of selection sort, the minimum element considering ascending order from the unsorted subarray is picked and moved to the sorted subarray.
Following example explains the above steps: Attention reader! Auxiliary Space: O 1 The good thing about selection sort is it never makes more than O n swaps and can be useful when memory write is a costly operation.
Exercise : Sort an array of strings using Selection Sort Stability : The default implementation is not stable. However it can be made stable. Please see stable selection sort for details. In Place : Yes, it does not require extra space. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
Skip to content. Change Language. Related Articles. Table of Contents. Save Article. The smallest element is selected from the unsorted array and swapped with the leftmost element, and that element becomes a part of the sorted array.
This process continues moving unsorted array boundary by one element to the right. For the first position in the sorted list, the whole list is scanned sequentially. The first position where 14 is stored presently, we search the whole list and find that 10 is the lowest value.
So we replace 14 with After one iteration 10, which happens to be the minimum value in the list, appears in the first position of the sorted list.
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